2k-3k(2k-3)=45

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Solution for 2k-3k(2k-3)=45 equation:



2k-3k(2k-3)=45
We move all terms to the left:
2k-3k(2k-3)-(45)=0
We multiply parentheses
-6k^2+2k+9k-45=0
We add all the numbers together, and all the variables
-6k^2+11k-45=0
a = -6; b = 11; c = -45;
Δ = b2-4ac
Δ = 112-4·(-6)·(-45)
Δ = -959
Delta is less than zero, so there is no solution for the equation

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