2k-3l-k+1ol=

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Solution for 2k-3l-k+1ol= equation:


Simplifying
2k + -3l + -1k + 1ol = 0

Reorder the terms:
2k + -1k + -3l + 1lo = 0

Combine like terms: 2k + -1k = 1k
1k + -3l + 1lo = 0

Solving
1k + -3l + 1lo = 0

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '3l' to each side of the equation.
1k + -3l + 3l + 1lo = 0 + 3l

Combine like terms: -3l + 3l = 0
1k + 0 + 1lo = 0 + 3l
1k + 1lo = 0 + 3l
Remove the zero:
1k + 1lo = 3l

Add '-1lo' to each side of the equation.
1k + 1lo + -1lo = 3l + -1lo

Combine like terms: 1lo + -1lo = 0
1k + 0 = 3l + -1lo
1k = 3l + -1lo

Divide each side by '1'.
k = 3l + -1lo

Simplifying
k = 3l + -1lo

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