2k-4=2(k-2)

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Solution for 2k-4=2(k-2) equation: 



2k-4=2(k-2)

We move all terms to the left:

2k-4-(2(k-2))=0



We calculate terms in parentheses: -(2(k-2)), so:

2(k-2)

We multiply parentheses

2k-4

Back to the equation:

-(2k-4)



We get rid of parentheses

2k-2k+4-4=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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