2k-5/2=5

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Solution for 2k-5/2=5 equation:



2k-5/2=5
We move all terms to the left:
2k-5/2-(5)=0
determiningTheFunctionDomain 2k-5-5/2=0
We multiply all the terms by the denominator
2k*2-5-5*2=0
We add all the numbers together, and all the variables
2k*2-15=0
Wy multiply elements
4k-15=0
We move all terms containing k to the left, all other terms to the right
4k=15
k=15/4
k=3+3/4

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