2k-5/2=5

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Solution for 2k-5/2=5 equation: 



2k-5/2=5

We move all terms to the left:

2k-5/2-(5)=0

determiningTheFunctionDomain
2k-5-5/2=0

We multiply all the terms by the denominator


2k*2-5-5*2=0

We add all the numbers together, and all the variables

2k*2-15=0

Wy multiply elements

4k-15=0

We move all terms containing k to the left, all other terms to the right

4k=15

k=15/4

k=3+3/4

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