2k-7(k+3)=-6

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Solution for 2k-7(k+3)=-6 equation: 



2k-7(k+3)=-6

We move all terms to the left:

2k-7(k+3)-(-6)=0

We add all the numbers together, and all the variables

2k-7(k+3)+6=0

We multiply parentheses

2k-7k-21+6=0

We add all the numbers together, and all the variables

-5k-15=0

We move all terms containing k to the left, all other terms to the right

-5k=15

k=15/-5

k=-3

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