2k/3+2=k/3+5

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Solution for 2k/3+2=k/3+5 equation: 



2k/3+2=k/3+5

We move all terms to the left:

2k/3+2-(k/3+5)=0

We get rid of parentheses

2k/3-k/3-5+2=0

We multiply all the terms by the denominator


2k-k-5*3+2*3=0

We add all the numbers together, and all the variables

k-9=0

We move all terms containing k to the left, all other terms to the right

k=9

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