2k/3k=6/9k

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Solution for 2k/3k=6/9k equation: 


k in (-oo:+oo)

((2*k)/3)*k = (6/9)*k // - (6/9)*k

((2*k)/3)*k-((6/9)*k) = 0

((2*k)/3)*k+(-2/3)*k = 0

2/3*k^2-2/3*k = 0

DELTA = (-2/3)^2-(0*2/3*4)

DELTA = 4/9

DELTA > 0

k = ((4/9)^(1/2)+2/3)/(2/3*2) or k = (2/3-(4/9)^(1/2))/(2/3*2)

k = 1 or k = 0

k in { 0, 1 }

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