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2k^2=30k-100
We move all terms to the left:
2k^2-(30k-100)=0
We get rid of parentheses
2k^2-30k+100=0
a = 2; b = -30; c = +100;
Δ = b2-4ac
Δ = -302-4·2·100
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-10}{2*2}=\frac{20}{4} =5 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+10}{2*2}=\frac{40}{4} =10 $
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