2l+3=7/l=5

Solution for 2l+3=7/l=5 equation:

2l+3=7/l=5

We move all terms to the left:

2l+3-(7/l)=0


Domain of the equation: l)!=0

l!=0/1

l!=0

l∈R


We add all the numbers together, and all the variables

2l-(+7/l)+3=0

We get rid of parentheses

2l-7/l+3=0

We multiply all the terms by the denominator


2l*l+3*l-7=0

We add all the numbers together, and all the variables

3l+2l*l-7=0

Wy multiply elements

2l^2+3l-7=0

a = 2; b = 3; c = -7;
Δ = b2-4ac
Δ = 32-4·2·(-7)
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$l_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$l_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$l_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{65}}{2*2}=\frac{-3-\sqrt{65}}{4}
$
$l_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{65}}{2*2}=\frac{-3+\sqrt{65}}{4}
$