2ln(x3/3)+ln(3x)=0

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Solution for 2ln(x3/3)+ln(3x)=0 equation:


D( x )

3*x <= 0

(x^3)/3 <= 0

3*x <= 0

3*x <= 0

3*x+0 <= 0 // - 0

3*x <= 0 // : 3

x <= 0/3

x <= 0

(x^3)/3 <= 0

(x^3)/3 <= 0

1/3*x^3 <= 0

1/3*x^3 <= 0 // : 1/3

x^3 <= 0/1/3

x^3 <= 0

x^3 <= 0 // ^ 1/3

x <= 0

x in (-oo:0>

x in (0:+oo)

2*ln((x^3)/3)+ln(3*x) = 0

ln(1*((x^3)/3)^2)+ln(3*x) = 0

ln(1*3*x*((x^3)/3)^2) = 0

ln(3*x*((x^3)/3)^2) = 0

ln(3*x*((x^3)/3)^2) = ln(e^0)

3*x*((x^3)/3)^2 = e^0

3*x*((x^3)/3)^2-e^0 = 0

1/3*x^7 = 1 // : 1/3

x^7 = 3

x^7 = 3 // ^ 1/7

x = 3^(1/7)

x = 3^(1/7)

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