2log(x+1)=log(2x+13)

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Solution for 2log(x+1)=log(2x+13) equation:


Simplifying
2log(x + 1) = log(2x + 13)

Reorder the terms:
2glo(1 + x) = log(2x + 13)
(1 * 2glo + x * 2glo) = log(2x + 13)
(2glo + 2glox) = log(2x + 13)

Reorder the terms:
2glo + 2glox = glo(13 + 2x)
2glo + 2glox = (13 * glo + 2x * glo)
2glo + 2glox = (13glo + 2glox)

Add '-2glox' to each side of the equation.
2glo + 2glox + -2glox = 13glo + 2glox + -2glox

Combine like terms: 2glox + -2glox = 0
2glo + 0 = 13glo + 2glox + -2glox
2glo = 13glo + 2glox + -2glox

Combine like terms: 2glox + -2glox = 0
2glo = 13glo + 0
2glo = 13glo

Solving
2glo = 13glo

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '-13glo' to each side of the equation.
2glo + -13glo = 13glo + -13glo

Combine like terms: 2glo + -13glo = -11glo
-11glo = 13glo + -13glo

Combine like terms: 13glo + -13glo = 0
-11glo = 0

Divide each side by '-11'.
glo = 0

Simplifying
glo = 0

The solution to this equation could not be determined.

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