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2m(m-2)=4-2m
We move all terms to the left:
2m(m-2)-(4-2m)=0
We add all the numbers together, and all the variables
2m(m-2)-(-2m+4)=0
We multiply parentheses
2m^2-4m-(-2m+4)=0
We get rid of parentheses
2m^2-4m+2m-4=0
We add all the numbers together, and all the variables
2m^2-2m-4=0
a = 2; b = -2; c = -4;
Δ = b2-4ac
Δ = -22-4·2·(-4)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-6}{2*2}=\frac{-4}{4} =-1 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+6}{2*2}=\frac{8}{4} =2 $
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