2m(m-7)=6-3m

Solution for 2m(m-7)=6-3m equation:

2m(m-7)=6-3m

We move all terms to the left:

2m(m-7)-(6-3m)=0

We add all the numbers together, and all the variables

2m(m-7)-(-3m+6)=0

We multiply parentheses

2m^2-14m-(-3m+6)=0

We get rid of parentheses

2m^2-14m+3m-6=0

We add all the numbers together, and all the variables

2m^2-11m-6=0

a = 2; b = -11; c = -6;
Δ = b2-4ac
Δ = -112-4·2·(-6)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-13}{2*2}=\frac{-2}{4}
=-1/2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+13}{2*2}=\frac{24}{4}
=6
$