2m+(-6)+4m=12

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Solution for 2m+(-6)+4m=12 equation: 



2m+(-6)+4m=12

We move all terms to the left:

2m+(-6)+4m-(12)=0

determiningTheFunctionDomain
2m+4m-12+(-6)=0

We add all the numbers together, and all the variables

6m-18=0

We move all terms containing m to the left, all other terms to the right

6m=18

m=18/6

m=3

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