2m+3(m+4)=27

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Solution for 2m+3(m+4)=27 equation:



2m+3(m+4)=27
We move all terms to the left:
2m+3(m+4)-(27)=0
We multiply parentheses
2m+3m+12-27=0
We add all the numbers together, and all the variables
5m-15=0
We move all terms containing m to the left, all other terms to the right
5m=15
m=15/5
m=3

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