2m+3(m+4)=27

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Solution for 2m+3(m+4)=27 equation: 



2m+3(m+4)=27

We move all terms to the left:

2m+3(m+4)-(27)=0

We multiply parentheses

2m+3m+12-27=0

We add all the numbers together, and all the variables

5m-15=0

We move all terms containing m to the left, all other terms to the right

5m=15

m=15/5

m=3

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