2m+3(m-7)=44

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Solution for 2m+3(m-7)=44 equation: 



2m+3(m-7)=44

We move all terms to the left:

2m+3(m-7)-(44)=0

We multiply parentheses

2m+3m-21-44=0

We add all the numbers together, and all the variables

5m-65=0

We move all terms containing m to the left, all other terms to the right

5m=65

m=65/5

m=13

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