2m+3=1-6(m-1)

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Solution for 2m+3=1-6(m-1) equation: 



2m+3=1-6(m-1)

We move all terms to the left:

2m+3-(1-6(m-1))=0



We calculate terms in parentheses: -(1-6(m-1)), so:

1-6(m-1)

determiningTheFunctionDomain
-6(m-1)+1

We multiply parentheses

-6m+6+1

We add all the numbers together, and all the variables

-6m+7

Back to the equation:

-(-6m+7)



We get rid of parentheses

2m+6m-7+3=0

We add all the numbers together, and all the variables

8m-4=0

We move all terms containing m to the left, all other terms to the right

8m=4

m=4/8

m=1/2

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