2m+4-3m=8m(m-1)

Solution for 2m+4-3m=8m(m-1) equation:

2m+4-3m=8m(m-1)

We move all terms to the left:

2m+4-3m-(8m(m-1))=0

We add all the numbers together, and all the variables

-1m-(8m(m-1))+4=0


We calculate terms in parentheses: -(8m(m-1)), so:

8m(m-1)

We multiply parentheses

8m^2-8m

Back to the equation:

-(8m^2-8m)


We get rid of parentheses

-8m^2-1m+8m+4=0

We add all the numbers together, and all the variables

-8m^2+7m+4=0

a = -8; b = 7; c = +4;
Δ = b2-4ac
Δ = 72-4·(-8)·4
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{177}}{2*-8}=\frac{-7-\sqrt{177}}{-16}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{177}}{2*-8}=\frac{-7+\sqrt{177}}{-16}
$