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2m+5=5-(-2m)
We move all terms to the left:
2m+5-(5-(-2m))=0
We calculate terms in parentheses: -(5-(-2m)), so:We get rid of parentheses
5-(-2m)
determiningTheFunctionDomain -(-2m)+5
We get rid of parentheses
2m+5
Back to the equation:
-(2m+5)
2m-2m-5+5=0
We add all the numbers together, and all the variables
=0
m=0/1
m=0
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