2m+6=(m+4)/3

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Solution for 2m+6=(m+4)/3 equation: 



2m+6=(m+4)/3

We move all terms to the left:

2m+6-((m+4)/3)=0

We multiply all the terms by the denominator


2m*3)-((m+4)+6*3)=0

We add all the numbers together, and all the variables

2m*3)-((m+4)=0

Wy multiply elements

6m^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{12}=0$

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