2m+8+2(2m-3)=3(m+3)

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Solution for 2m+8+2(2m-3)=3(m+3) equation: 



2m+8+2(2m-3)=3(m+3)

We move all terms to the left:

2m+8+2(2m-3)-(3(m+3))=0

We multiply parentheses

2m+4m-(3(m+3))-6+8=0



We calculate terms in parentheses: -(3(m+3)), so:

3(m+3)

We multiply parentheses

3m+9

Back to the equation:

-(3m+9)



We add all the numbers together, and all the variables

6m-(3m+9)+2=0

We get rid of parentheses

6m-3m-9+2=0

We add all the numbers together, and all the variables

3m-7=0

We move all terms containing m to the left, all other terms to the right

3m=7

m=7/3

m=2+1/3

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