2m+m+(m+10)2m=180

Solution for 2m+m+(m+10)2m=180 equation:

2m+m+(m+10)2m=180

We move all terms to the left:

2m+m+(m+10)2m-(180)=0

We add all the numbers together, and all the variables

3m+(m+10)2m-180=0

We multiply parentheses

2m^2+3m+20m-180=0

We add all the numbers together, and all the variables

2m^2+23m-180=0

a = 2; b = 23; c = -180;
Δ = b2-4ac
Δ = 232-4·2·(-180)
Δ = 1969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{1969}}{2*2}=\frac{-23-\sqrt{1969}}{4}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{1969}}{2*2}=\frac{-23+\sqrt{1969}}{4}
$