2m-12/m=10/7

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Solution for 2m-12/m=10/7 equation:


D( m )

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

2*m-(12/m) = 10/7 // - 10/7

2*m-(12/m)-(10/7) = 0

2*m-12*m^-1-10/7 = 0

2*m^1-12*m^-1-10/7*m^0 = 0

(2*m^2-10/7*m^1-12*m^0)/(m^1) = 0 // * m^2

m^1*(2*m^2-10/7*m^1-12*m^0) = 0

m^1

2*m^2+(-10/7)*m-12 = 0

2*m^2+(-10/7)*m-12 = 0

DELTA = (-10/7)^2-(-12*2*4)

DELTA = 4804/49

DELTA > 0

m = ((4804/49)^(1/2)-(-10/7))/(2*2) or m = (-(-10/7)-(4804/49)^(1/2))/(2*2)

m = ((4804/49)^(1/2)+10/7)/4 or m = (10/7-(4804/49)^(1/2))/4

m in { (10/7-(4804/49)^(1/2))/4, ((4804/49)^(1/2)+10/7)/4}

m in { (10/7-(4804/49)^(1/2))/4, ((4804/49)^(1/2)+10/7)/4 }

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