2m-2(1-3m)=5(7m+5)

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Solution for 2m-2(1-3m)=5(7m+5) equation: 



2m-2(1-3m)=5(7m+5)

We move all terms to the left:

2m-2(1-3m)-(5(7m+5))=0

We add all the numbers together, and all the variables

2m-2(-3m+1)-(5(7m+5))=0

We multiply parentheses

2m+6m-(5(7m+5))-2=0



We calculate terms in parentheses: -(5(7m+5)), so:

5(7m+5)

We multiply parentheses

35m+25

Back to the equation:

-(35m+25)



We add all the numbers together, and all the variables

8m-(35m+25)-2=0

We get rid of parentheses

8m-35m-25-2=0

We add all the numbers together, and all the variables

-27m-27=0

We move all terms containing m to the left, all other terms to the right

-27m=27

m=27/-27

m=-1

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