2m-3(m+1)=4(m+)

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Solution for 2m-3(m+1)=4(m+) equation: 



2m-3(m+1)=4(m+)

We move all terms to the left:

2m-3(m+1)-(4(m+))=0

We add all the numbers together, and all the variables

2m-3(m+1)-(4(+m))=0

We multiply parentheses

2m-3m-(4(+m))-3=0



We calculate terms in parentheses: -(4(+m)), so:

4(+m)

We multiply parentheses

4m

Back to the equation:

-(4m)



We add all the numbers together, and all the variables

-5m-3=0

We move all terms containing m to the left, all other terms to the right

-5m=3

m=3/-5

m=-3/5

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