2m-3(m1)=4(m+3)

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Solution for 2m-3(m1)=4(m+3) equation: 



2m-3(m1)=4(m+3)

We move all terms to the left:

2m-3(m1)-(4(m+3))=0

We add all the numbers together, and all the variables

-1m-(4(m+3))=0



We calculate terms in parentheses: -(4(m+3)), so:

4(m+3)

We multiply parentheses

4m+12

Back to the equation:

-(4m+12)



We get rid of parentheses

-1m-4m-12=0

We add all the numbers together, and all the variables

-5m-12=0

We move all terms containing m to the left, all other terms to the right

-5m=12

m=12/-5

m=-2+2/5

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