2m-35=2m-5(1+6m)

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Solution for 2m-35=2m-5(1+6m) equation: 



2m-35=2m-5(1+6m)

We move all terms to the left:

2m-35-(2m-5(1+6m))=0

We add all the numbers together, and all the variables

2m-(2m-5(6m+1))-35=0



We calculate terms in parentheses: -(2m-5(6m+1)), so:

2m-5(6m+1)

We multiply parentheses

2m-30m-5

We add all the numbers together, and all the variables

-28m-5

Back to the equation:

-(-28m-5)



We get rid of parentheses

2m+28m+5-35=0

We add all the numbers together, and all the variables

30m-30=0

We move all terms containing m to the left, all other terms to the right

30m=30

m=30/30

m=1

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