2m-3=2(6-m)+7m

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Solution for 2m-3=2(6-m)+7m equation: 



2m-3=2(6-m)+7m

We move all terms to the left:

2m-3-(2(6-m)+7m)=0

We add all the numbers together, and all the variables

2m-(2(-1m+6)+7m)-3=0



We calculate terms in parentheses: -(2(-1m+6)+7m), so:

2(-1m+6)+7m

We add all the numbers together, and all the variables

7m+2(-1m+6)

We multiply parentheses

7m-2m+12

We add all the numbers together, and all the variables

5m+12

Back to the equation:

-(5m+12)



We get rid of parentheses

2m-5m-12-3=0

We add all the numbers together, and all the variables

-3m-15=0

We move all terms containing m to the left, all other terms to the right

-3m=15

m=15/-3

m=-5

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