2m-4(m+3)=(2m+10)

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Solution for 2m-4(m+3)=(2m+10) equation: 



2m-4(m+3)=(2m+10)

We move all terms to the left:

2m-4(m+3)-((2m+10))=0

We multiply parentheses

2m-4m-((2m+10))-12=0



We calculate terms in parentheses: -((2m+10)), so:

(2m+10)

We get rid of parentheses

2m+10

Back to the equation:

-(2m+10)



We add all the numbers together, and all the variables

-2m-(2m+10)-12=0

We get rid of parentheses

-2m-2m-10-12=0

We add all the numbers together, and all the variables

-4m-22=0

We move all terms containing m to the left, all other terms to the right

-4m=22

m=22/-4

m=-5+1/2

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