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x in (-oo:+oo)
(2*m)/5 = (i/3)*(2*m-12) // - (i/3)*(2*m-12)
(2*m)/5-((i/3)*(2*m-12)) = 0
(2*m)/5-1*1/3*i*(2*m-12) = 0
(-1*1/3*5*i*(2*m-12))/5+(2*m)/5 = 0
2*m-1*1/3*5*i*(2*m-12) = 0
20*i-10/3*i*m+2*m = 0
(20*i-10/3*i*m+2*m)/5 = 0
(20*i-10/3*i*m+2*m)/5 = 0 // * 5
20*i-10/3*i*m+2*m = 0
x belongs to the empty set
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