2m/5=i/3(2m-12)

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Solution for 2m/5=i/3(2m-12) equation:


x in (-oo:+oo)

(2*m)/5 = (i/3)*(2*m-12) // - (i/3)*(2*m-12)

(2*m)/5-((i/3)*(2*m-12)) = 0

(2*m)/5-1*1/3*i*(2*m-12) = 0

(-1*1/3*5*i*(2*m-12))/5+(2*m)/5 = 0

2*m-1*1/3*5*i*(2*m-12) = 0

20*i-10/3*i*m+2*m = 0

(20*i-10/3*i*m+2*m)/5 = 0

(20*i-10/3*i*m+2*m)/5 = 0 // * 5

20*i-10/3*i*m+2*m = 0

x belongs to the empty set

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