2m2+13m+12=0

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Solution for 2m2+13m+12=0 equation: 



2m^2+13m+12=0

a = 2; b = 13; c = +12;
Δ = b2-4ac
Δ = 132-4·2·12
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{73}}{2*2}=\frac{-13-\sqrt{73}}{4}
$


$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{73}}{2*2}=\frac{-13+\sqrt{73}}{4}
$

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