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2m^2-5m-63=0
a = 2; b = -5; c = -63;
Δ = b2-4ac
Δ = -52-4·2·(-63)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-23}{2*2}=\frac{-18}{4} =-4+1/2 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+23}{2*2}=\frac{28}{4} =7 $
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