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2m^2=2m-12=0
We move all terms to the left:
2m^2-(2m-12)=0
We get rid of parentheses
2m^2-2m+12=0
a = 2; b = -2; c = +12;
Δ = b2-4ac
Δ = -22-4·2·12
Δ = -92
Delta is less than zero, so there is no solution for the equation
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