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2n(2)+7=-4n+5
We move all terms to the left:
2n(2)+7-(-4n+5)=0
We add all the numbers together, and all the variables
2n^2-(-4n+5)+7=0
We get rid of parentheses
2n^2+4n-5+7=0
We add all the numbers together, and all the variables
2n^2+4n+2=0
a = 2; b = 4; c = +2;
Δ = b2-4ac
Δ = 42-4·2·2
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$n=\frac{-b}{2a}=\frac{-4}{4}=-1$
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