2n(7n+1)=0

Solution for 2n(7n+1)=0 equation:

2n(7n+1)=0

We multiply parentheses

14n^2+2n=0

a = 14; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·14·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*14}=\frac{-4}{28}
=-1/7
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*14}=\frac{0}{28}
=0
$