2n(n-1)+4n=2(3n-1

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Solution for 2n(n-1)+4n=2(3n-1 equation: 



2n(n-1)+4n=2(3n-1

We move all terms to the left:

2n(n-1)+4n-(2(3n-1)=0

We add all the numbers together, and all the variables

4n+2n(n-1)-(2(3n-1)=0

We multiply parentheses

2n^2+4n-2n-(2(3n-1)=0



We calculate terms in parentheses: -(2(3n-1), so:

2(3n-1



We add all the numbers together, and all the variables

2n^2+2n-(2(3n-1)=0



We calculate terms in parentheses: -(2(3n-1), so:

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