2n+1/n+2=5/4

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Solution for 2n+1/n+2=5/4 equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

2*n+1/n+2 = 5/4 // - 5/4

2*n+1/n-(5/4)+2 = 0

2*n+1/n-5/4+2 = 0

2*n^1+1*n^-1+3/4*n^0 = 0

(2*n^2+3/4*n^1+1*n^0)/(n^1) = 0 // * n^2

n^1*(2*n^2+3/4*n^1+1*n^0) = 0

n^1

2*n^2+(3/4)*n+1 = 0

2*n^2+(3/4)*n+1 = 0

DELTA = (3/4)^2-(1*2*4)

DELTA = -119/16

DELTA < 0

n in { } 

n belongs to the empty set

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