2n+10+3n=4(n-1)

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Solution for 2n+10+3n=4(n-1) equation: 



2n+10+3n=4(n-1)

We move all terms to the left:

2n+10+3n-(4(n-1))=0

We add all the numbers together, and all the variables

5n-(4(n-1))+10=0



We calculate terms in parentheses: -(4(n-1)), so:

4(n-1)

We multiply parentheses

4n-4

Back to the equation:

-(4n-4)



We get rid of parentheses

5n-4n+4+10=0

We add all the numbers together, and all the variables

n+14=0

We move all terms containing n to the left, all other terms to the right

n=-14

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