2n+2(n-5)=-2(n-8)+2n

Solution for 2n+2(n-5)=-2(n-8)+2n equation:

2n+2(n-5)=-2(n-8)+2n

We move all terms to the left:

2n+2(n-5)-(-2(n-8)+2n)=0

We multiply parentheses

2n+2n-(-2(n-8)+2n)-10=0


We calculate terms in parentheses: -(-2(n-8)+2n), so:

-2(n-8)+2n

We add all the numbers together, and all the variables

2n-2(n-8)

We multiply parentheses

2n-2n+16

We add all the numbers together, and all the variables

16

Back to the equation:

-(16)


We add all the numbers together, and all the variables

4n-26=0

We move all terms containing n to the left, all other terms to the right

4n=26

n=26/4

n=6+1/2