2n+2(n-5)=-2(n-8)+8n

Solution for 2n+2(n-5)=-2(n-8)+8n equation:

2n+2(n-5)=-2(n-8)+8n

We move all terms to the left:

2n+2(n-5)-(-2(n-8)+8n)=0

We multiply parentheses

2n+2n-(-2(n-8)+8n)-10=0


We calculate terms in parentheses: -(-2(n-8)+8n), so:

-2(n-8)+8n

We add all the numbers together, and all the variables

8n-2(n-8)

We multiply parentheses

8n-2n+16

We add all the numbers together, and all the variables

6n+16

Back to the equation:

-(6n+16)


We add all the numbers together, and all the variables

4n-(6n+16)-10=0

We get rid of parentheses

4n-6n-16-10=0

We add all the numbers together, and all the variables

-2n-26=0

We move all terms containing n to the left, all other terms to the right

-2n=26

n=26/-2

n=-13