2n+23=6(n+1)+1

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Solution for 2n+23=6(n+1)+1 equation:



2n+23=6(n+1)+1
We move all terms to the left:
2n+23-(6(n+1)+1)=0
We calculate terms in parentheses: -(6(n+1)+1), so:
6(n+1)+1
We multiply parentheses
6n+6+1
We add all the numbers together, and all the variables
6n+7
Back to the equation:
-(6n+7)
We get rid of parentheses
2n-6n-7+23=0
We add all the numbers together, and all the variables
-4n+16=0
We move all terms containing n to the left, all other terms to the right
-4n=-16
n=-16/-4
n=+4

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