2n+3(1+n)=4(n-1)

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Solution for 2n+3(1+n)=4(n-1) equation: 



2n+3(1+n)=4(n-1)

We move all terms to the left:

2n+3(1+n)-(4(n-1))=0

We add all the numbers together, and all the variables

2n+3(n+1)-(4(n-1))=0

We multiply parentheses

2n+3n-(4(n-1))+3=0



We calculate terms in parentheses: -(4(n-1)), so:

4(n-1)

We multiply parentheses

4n-4

Back to the equation:

-(4n-4)



We add all the numbers together, and all the variables

5n-(4n-4)+3=0

We get rid of parentheses

5n-4n+4+3=0

We add all the numbers together, and all the variables

n+7=0

We move all terms containing n to the left, all other terms to the right

n=-7

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