2n+3(n+1)+2(n+2)=147

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Solution for 2n+3(n+1)+2(n+2)=147 equation: 



2n+3(n+1)+2(n+2)=147

We move all terms to the left:

2n+3(n+1)+2(n+2)-(147)=0

We multiply parentheses

2n+3n+2n+3+4-147=0

We add all the numbers together, and all the variables

7n-140=0

We move all terms containing n to the left, all other terms to the right

7n=140

n=140/7

n=20

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