2n+3(n-1)+4(n+2)=50

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Solution for 2n+3(n-1)+4(n+2)=50 equation: 



2n+3(n-1)+4(n+2)=50

We move all terms to the left:

2n+3(n-1)+4(n+2)-(50)=0

We multiply parentheses

2n+3n+4n-3+8-50=0

We add all the numbers together, and all the variables

9n-45=0

We move all terms containing n to the left, all other terms to the right

9n=45

n=45/9

n=5

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