2n+34=4(n+5)

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Solution for 2n+34=4(n+5) equation: 



2n+34=4(n+5)

We move all terms to the left:

2n+34-(4(n+5))=0



We calculate terms in parentheses: -(4(n+5)), so:

4(n+5)

We multiply parentheses

4n+20

Back to the equation:

-(4n+20)



We get rid of parentheses

2n-4n-20+34=0

We add all the numbers together, and all the variables

-2n+14=0

We move all terms containing n to the left, all other terms to the right

-2n=-14

n=-14/-2

n=+7

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