2n+3=3(n-1)

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Solution for 2n+3=3(n-1) equation: 



2n+3=3(n-1)

We move all terms to the left:

2n+3-(3(n-1))=0



We calculate terms in parentheses: -(3(n-1)), so:

3(n-1)

We multiply parentheses

3n-3

Back to the equation:

-(3n-3)



We get rid of parentheses

2n-3n+3+3=0

We add all the numbers together, and all the variables

-1n+6=0

We move all terms containing n to the left, all other terms to the right

-n=-6

n=-6/-1

n=+6

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