2n+3n=4;-n+2=5

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Solution for 2n+3n=4;-n+2=5 equation: 



2n+3n=4-n+2=5

We move all terms to the left:

2n+3n-(4-n+2)=0

We add all the numbers together, and all the variables

2n+3n-(-1n+6)=0

We add all the numbers together, and all the variables

5n-(-1n+6)=0

We get rid of parentheses

5n+1n-6=0

We add all the numbers together, and all the variables

6n-6=0

We move all terms containing n to the left, all other terms to the right

6n=6

n=6/6

n=1

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