2n+5=4(n+2)-b

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Solution for 2n+5=4(n+2)-b equation:


Simplifying
2n + 5 = 4(n + 2) + -1b

Reorder the terms:
5 + 2n = 4(n + 2) + -1b

Reorder the terms:
5 + 2n = 4(2 + n) + -1b
5 + 2n = (2 * 4 + n * 4) + -1b
5 + 2n = (8 + 4n) + -1b

Reorder the terms:
5 + 2n = 8 + -1b + 4n

Solving
5 + 2n = 8 + -1b + 4n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-4n' to each side of the equation.
5 + 2n + -4n = 8 + -1b + 4n + -4n

Combine like terms: 2n + -4n = -2n
5 + -2n = 8 + -1b + 4n + -4n

Combine like terms: 4n + -4n = 0
5 + -2n = 8 + -1b + 0
5 + -2n = 8 + -1b

Add '-5' to each side of the equation.
5 + -5 + -2n = 8 + -5 + -1b

Combine like terms: 5 + -5 = 0
0 + -2n = 8 + -5 + -1b
-2n = 8 + -5 + -1b

Combine like terms: 8 + -5 = 3
-2n = 3 + -1b

Divide each side by '-2'.
n = -1.5 + 0.5b

Simplifying
n = -1.5 + 0.5b

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