2n+6+n+2=6(n-1)-7(3n-2)

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Solution for 2n+6+n+2=6(n-1)-7(3n-2) equation: 



2n+6+n+2=6(n-1)-7(3n-2)

We move all terms to the left:

2n+6+n+2-(6(n-1)-7(3n-2))=0

We add all the numbers together, and all the variables

3n-(6(n-1)-7(3n-2))+8=0



We calculate terms in parentheses: -(6(n-1)-7(3n-2)), so:

6(n-1)-7(3n-2)

We multiply parentheses

6n-21n-6+14

We add all the numbers together, and all the variables

-15n+8

Back to the equation:

-(-15n+8)



We get rid of parentheses

3n+15n-8+8=0

We add all the numbers together, and all the variables

18n=0

n=0/18

n=0

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