2n+8/n+4

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Solution for 2n+8/n+4 equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

2*n+8/n+4 = 0

2*n^1+8*n^-1+4*n^0 = 0

(2*n^2+4*n^1+8*n^0)/(n^1) = 0 // * n^2

n^1*(2*n^2+4*n^1+8*n^0) = 0

n^1

2*n^2+4*n+8 = 0

2*n^2+4*n+8 = 0

DELTA = 4^2-(2*4*8)

DELTA = -48

DELTA < 0

n in { } 

n belongs to the empty set

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